Download ACI 318-05 Mathcad in Concrete Structures by Seun Sambath PDF

By Seun Sambath

Building MANAGEMENT
Concept-Develop-Execute-Finish
__________________________________________________________________________________
Seun Sambath, PhD
Concrete Structures
(ACI 318-05)
in Mathcad
Sixth Edition
Phnom Penh 2010
___________________________________________________________________________________
Address: #M41, St.308, Sangkat Tonle Basac, Khan Chamkarmon,
Phnom Penh, Cambodia.
Tel: 012 659 848.

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Additional resources for ACI 318-05 Mathcad in Concrete Structures

Example text

Determination of Flexural Strength Given: b  d As f'c fy Find: ϕMn Step 1. Checking for steel ratio ρ= As b d ρ  ρmin : Steel reinforcement is not enough ρmin  ρ  ρmax : the beam is singly reinforced ρ  ρmax : the beam is doubly reinforced ρ = ρmax Step 2. 82  kN m E. 85 f'c 1 Step 1. 9 Mu Mn = ϕ Step 2. 85 f'c  R ρ  ρmax : the beam is doubly reinforced (concrete is not enough) ρ  ρmax : the beam is singly reinforced   As = max ρ ρmin  b  d (this is a required steel area) Step 3.

625 D. Determination of Flexural Strength Given: b  d As f'c fy Find: ϕMn Step 1. Checking for steel ratio ρ= As b d ρ  ρmin : Steel reinforcement is not enough ρmin  ρ  ρmax : the beam is singly reinforced ρ  ρmax : the beam is doubly reinforced ρ = ρmax Step 2. 82  kN m E. 85 f'c 1 Step 1. 9 Mu Mn = ϕ Step 2. 85 f'c  R ρ  ρmax : the beam is doubly reinforced (concrete is not enough) ρ  ρmax : the beam is singly reinforced   As = max ρ ρmin  b  d (this is a required steel area) Step 3.

Determination of Flexural Strength Given: b  d d t d' As A's f'c fy Find: ϕMn Step 1. max As = ρ b  d Step 2. 1. 2. 85 f'c a β1 f's = Es ε's  fy c Step 3. 783  kN m D. Design of Doubly Reinforced Beam Given: M u b  d d t d' f'c fs Find: As A's Step 1. 85 β1   fy ε u  ε t   ϕ = ϕ εt Step 2. 85 f'c b a M n = As fy   d   2  M u  ϕMn : the beam is singly reinforced M u  ϕMn : the beam is doubly reinforced Step 3. 575 cm 2 E. Determination of Tensile Steel Area Given: M u b  d d t d' A's f'c fy Find: As Step 1.

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